The following questions are based on Chart 12221TR, Chesapeake Bay Entrance, and the supporting publications. Your present course is 202°T and your vessel's engines are turning RPMs for 18 knots. Your height of eye is 54 feet (16.5 meters) and your vessel's draft is 28 feet (8.5 meters). Use 10°W variation where required. At 0800 your position is LAT 37°21.0'N, LONG 75°32.0'W. Assuming that there is no set and drift, what time would your vessel cross the 60-foot curve?
Study on the go
Take your USCG credential exam practice questions offline with the mobile app.
Download AppRelated Questions
At 2200, you alter course to 204°T, at 14 knots. You expect a current on this le...
View questionAt 0800 you reduce speed from sea speed. Speed was reduced by the time you passe...
View questionAt 0725 you determined your vessel's position to be 37°15.5'N, 75°33.2'W. Assumi...
View questionAt 1022 when you complete the evacuation, you get underway on course 098°T and o...
View questionFrom your 2030 fix you change course to 195°T, and leave the engine speed at 14...
View questionAt 0907 you change course to 224°T, and your speed is now 13.0 knots. At 0939 Ch...
View questionFrom your 0820 position you change course to your rendezvous position, one mile...
View questionAt 2030 you take the following bearings: Sand Shoal Inlet South Light: 275°T...
View questionAt 0847 you take a round of bearings as follows: Middle Ground Shoal Light 2...
View questionFrom your 0939 position, you wish to change course in order to pass 0.3 mile nor...
View question